HL AI · Calculus

Optimisation in context (IB Math AI HL)

Updated October 2026

Quick answer: Write the quantity to optimise in terms of two variables, use the constraint to remove one, differentiate, and solve f′(x) = 0. Then justify the type of point with the second derivative or a sign change of f′(x), and answer in context with units.

Maximise a profit or minimise a surface area: set up the function from the context, use the constraint to reduce it to one variable, solve f′(x) = 0 and justify that you have a maximum or a minimum.

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Worked example

A closed cylindrical can must hold 500 cm³. Find the radius that minimises the surface area, justify that it is a minimum, and give the least surface area.

  1. Volume: πr²h = 500, so h = 500 ÷ (πr²).
  2. Surface area: S = 2πr² + 2πrh = 2πr² + 1000/r.
  3. S′(r) = 4πr − 1000/r² = 0 gives r³ = 250/π, so r ≈ 4.30 cm (and h ≈ 8.60 cm, twice the radius).
  4. S″(r) = 4π + 2000/r³ ≈ 37.7 > 0 at r ≈ 4.30, so this is a minimum.
  5. S ≈ 2π(4.30)² + 1000 ÷ 4.30 ≈ 349 cm².

Answer: r ≈ 4.30 cm (h ≈ 8.60 cm); the least surface area is about 349 cm².

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5 quick questions on stationary points. No sign-in needed.

Find the \(y\)-coordinate of the stationary point of \(y = - 2 x^{2} + 12 x + 1\).
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Maths IA ideas that use optimisation in context

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Stretch yourself: original calculus and functions problems at Senior level (ages 16 to 18), with hints and full solutions: Problem S133. All 24 →

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FAQ

How do you show that a stationary point is a maximum or a minimum?

Use the second derivative: if f″(x) is negative at the point it is a maximum, and if positive a minimum. If f″(x) is zero or hard to find, show that f′(x) changes from positive to negative (maximum) or from negative to positive (minimum).

Can I use my calculator for optimisation in context?

Yes: a GDC is allowed on every HL AI paper, so practise the calculator method as well as the working.

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