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Geometric series sum to infinity: S∞ = u₁ / (1 − r)

The geometric series sum to infinity is S∞ = u₁ / (1 − r), for |r| < 1.

What each letter means

When to use it

When a geometric series goes on for ever and its terms shrink towards 0, for example a recurring decimal or the total distance travelled by a bouncing ball.

Worked example

Find the sum to infinity of \(24+18+13.5+\cdots\)

  1. \(r=\dfrac{18}{24}=0.75\), and \(|r|<1\)
  2. \(S_\infty=\dfrac{24}{1-0.75}=\dfrac{24}{0.25}\)

Answer: \(S_\infty=96\)

Common mistake

Using it when |r| ≥ 1. Then the terms do not shrink and the series has no sum to infinity.

On your course

CourseIn the exam
AA SLIn the IB formula booklet
AA HLIn the IB formula booklet
AI HLIn the IB formula booklet

From our own IB Maths formula sheets, in our words. The IB gives its booklet to schools, so we checked against our own copy: your teacher has the official one. Official: IB DP Mathematics page.

Practise and revise

Sum to infinity of a geometric series formula card: S∞ = u₁ / (1 − r), for |r| < 1. IB Math Revision
Sum to infinity of a geometric series formula card. Download the card (PNG) to save or print it.

Questions

What is the geometric series sum to infinity formula?

The geometric series sum to infinity is S∞ = u₁ / (1 − r), for |r| < 1. S_∞: the sum to infinity: the value the sums get closer and closer to; u₁: the first term; r: the common ratio, which must be between −1 and 1.

Is the sum to infinity of a geometric series given in the exam?

AA SL: in the IB formula booklet. AA HL: in the IB formula booklet. AI HL: in the IB formula booklet. This comes from our own IB Maths formula sheets; your teacher has the official booklet.

When does a geometric series have a sum to infinity?

Only when −1 < r < 1. The terms then shrink towards 0 and the sums settle at u₁ / (1 − r).

Our own wording, examples and card, checked by IB Math Revision. Not produced or endorsed by the International Baccalaureate Organization.