cos(A ± B) = cos A cos B ∓ sin A sin B: the sign in the middle is the opposite of the sign in the bracket.
tan(A ± B) = (tan A ± tan B) / (1 ∓ tan A tan B).
Put B = A for the double-angle formulas: sin 2A = 2 sin A cos A; cos 2A = cos²A − sin²A = 2cos²A − 1 = 1 − 2sin²A; tan 2A = 2 tan A / (1 − tan²A).
Exact values: split the angle into two you know, such as 75° = 45° + 30° or 15° = 45° − 30°.
In a proof, start from one side and work to the other, and pick the form of cos 2A that cancels what you have: 2cos²A − 1 clears a +1, 1 − 2sin²A clears a −1.
Worked example
Find the exact value of sin 75°, then show that sin 2θ / (1 + cos 2θ) = tan θ.
sin 75° = sin(45° + 30°) = sin 45° cos 30° + cos 45° sin 30°.
= (√2/2)(√3/2) + (√2/2)(1/2) = (√6 + √2)/4.
For the identity, use cos 2θ = 2cos²θ − 1, so the 1 cancels: 1 + cos 2θ = 2cos²θ.
sin 2θ / (1 + cos 2θ) = 2 sin θ cos θ / (2cos²θ) = sin θ / cos θ = tan θ.
Answer: sin 75° = (√6 + √2)/4, and the left side simplifies to tan θ (for cos θ ≠ 0).
Where can I practise compound and double-angle formulas questions?
On the Reciprocal and Inverse Trig Functions questions page: 58 exam-style HL AA questions with full mark schemes, plus free step-by-step worked examples.
Can I use my calculator for compound and double-angle formulas?
In HL AA, Paper 1 is non-calculator and the other papers allow a GDC, so learn the exact method as well as the calculator one.