HL AA · Geometry and Trigonometry

Compound and double-angle formulas (IB Math AA HL)

Updated October 2026

sin(A±B), cos(A±B), plus their double-angle variants. HL AA Paper 1 uses these to prove identities or solve equations.

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Key ideas

Worked example

Find the exact value of sin 75°, then show that sin 2θ / (1 + cos 2θ) = tan θ.

  1. sin 75° = sin(45° + 30°) = sin 45° cos 30° + cos 45° sin 30°.
  2. = (√2/2)(√3/2) + (√2/2)(1/2) = (√6 + √2)/4.
  3. For the identity, use cos 2θ = 2cos²θ − 1, so the 1 cancels: 1 + cos 2θ = 2cos²θ.
  4. sin 2θ / (1 + cos 2θ) = 2 sin θ cos θ / (2cos²θ) = sin θ / cos θ = tan θ.

Answer: sin 75° = (√6 + √2)/4, and the left side simplifies to tan θ (for cos θ ≠ 0).

Exam-style HL AA questions on this topic

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5 quick questions on trigonometric identities. No sign-in needed.

\(\cos\theta = \frac{12}{13}\) and \(\theta\) is in the fourth quadrant. Find the exact value of \(\sin 2\theta\).
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Maths IA ideas that use compound and double-angle formulas

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Revise Compound and double-angle formulas for the exam

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Formulas in this topic: Trig identities. All formulas A–Z

FAQ

Where can I practise compound and double-angle formulas questions?

On the Reciprocal and Inverse Trig Functions questions page: 58 exam-style HL AA questions with full mark schemes, plus free step-by-step worked examples.

Can I use my calculator for compound and double-angle formulas?

In HL AA, Paper 1 is non-calculator and the other papers allow a GDC, so learn the exact method as well as the calculator one.

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