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TI-84 Plus CE lesson 8: Derivatives, integrals and the derivative graph

The TI-84 Plus CE works out a derivative at a point and a definite integral in one line, and it can draw the graph of f′(x) next to f(x). Seeing the two graphs together is the fastest way to understand, and check, where a function has its maximum and minimum points.

Objective

Find derivatives at a point and definite integrals, draw the graph of y = f′(x) and read it, and find areas and distances, all in Rad mode.

By the end, students can:

Which courses this lesson suits

AA Paper 1 is calculator-free: use these skills on Papers 2 and 3, and to check Paper 1-style practice.

Before you start

Set Rad mode: mode, move to RADIAN, enter, then 2nd mode (QUIT). Calculus with trig functions needs radians.

The key presses, step by step

Every key is shown as it is printed on the calculator, like 2nd or enter. A second function (printed above a key) is 2nd then that key; a menu item is chosen by its number, or by moving to it and pressing enter.

  1. Derivative at a point: press math 8. The d/dx template appears. Type X in the small box after d/d, the function X³ − 6X² + 9X + 1 in the brackets, and 2 after X =. Press enter: −2.999999.

    The calculator finds the gradient numerically, so the last digits can be off: −2.999999 means −3. Write f′(2) = −3.

    TI-84 Plus CE lesson 8 screen: Home screen: d/dx, showing the d/dx template giving −2.999999 at X = 2
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  2. Definite integral: math 9. Type the lower limit 0, the upper limit 2, the function, and X after d. enter: 8.

    TI-84 Plus CE lesson 8 screen: Home screen: integral, showing the integral from 0 to 2 giving 8
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  3. Use Y1 instead of retyping. Put Y1 = X³ − 6X² + 9X + 1 in y=. On the home screen, inside a template, press alpha trace (the shortcut menu above trace) and choose Y1. For example d/dX(Y1)|X=0.5 gives 3.750001.

    Change Y1 once and every calculation that uses it follows: no typing slips between parts of a question.

    TI-84 Plus CE lesson 8 screen: Home screen: using Y1, showing d/dX(Y1) at X = 0.5 giving 3.750001, and the integral of Y1 from 0 to 2
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  4. Draw the derivative graph. In y= move to Y2 and press math 8. Type X in the d/d box, Y1 in the brackets (alpha trace, Y1), and X after X = (not a number). So Y2 = d/dX(Y1)|X=X.

    Change the view to see both: window, Xmin = −1, Xmax = 5, Ymin = −4, Ymax = 8, then graph.

    Y2 is the gradient of Y1 at every x. Where Y1 climbs, Y2 is above the axis; where Y1 falls, Y2 is below.

    TI-84 Plus CE lesson 8 screen: Graph of f and f′, showing y = x³ − 6x² + 9x + 1 in blue with its derivative 3x² − 12x + 9 in red, crossing the x-axis at x = 1 and x = 3
    f (blue) and the derivative graph f′ (red) in the window −1 ≤ x ≤ 5, −4 ≤ y ≤ 8 (our drawing of the TI-84 Plus CE screen, not a photo).
  5. Read the link. 2nd trace (CALC) 2:zero, press ▼ to move to Y2, and answer Left Bound?, Right Bound? and Guess? around x = 1, then again around x = 3. Then CALC 4:maximum on Y1 near x = 1 and 3:minimum near x = 3: the same x-values.

    f′(x) = 0 exactly where f has a turning point. The last digits may wobble (something like 0.9999998 instead of 1): round to 3 s.f.

    TI-84 Plus CE lesson 8 screen: CALC zero on Y2, showing CALC zero on the derivative graph, with the cursor where Y2 crosses the x-axis at x = 1
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  6. Areas from the graph. 2nd trace (CALC) 7:∫f(x)dx on Y1, Lower Limit? 0 enter, Upper Limit? 2 enter: the region is shaded and ∫f(x)dx = 8 appears. (6:dy/dx gives the gradient at the x you type.)

    TI-84 Plus CE lesson 8 screen: CALC ∫f(x)dx, showing the area under y = x³ − 6x² + 9x + 1 from 0 to 2 shaded, ∫f(x)dx = 8
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  7. Area between two curves. In y= type Y3 = X + 1 and turn Y2 off (move to its = sign and press enter). CALC 5:intersect: First curve? Y1 enter, then ▼ to Y3 for Second curve? enter, then a guess. Y3 meets Y1 at x = 0, 2 and 4. Between 0 and 2 Y1 is on top; between 2 and 4 Y3 is. So area = ∫₀²(Y1 − Y3)dX + ∫₂⁴(Y3 − Y1)dX = 4 + 4 = 8.

    Or type ∫₀⁴abs(Y1 − Y3)dX in one go: abs( is math, ► to NUM, 1:abs(. Splitting at the crossings is what to write down.

    TI-84 Plus CE lesson 8 screen: Home screen: area between curves, showing the two integrals 4 and 4
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).

Your turn: check your understanding

Try these straight after the key presses, on your own calculator, before looking at the answers.

  1. With Y1 = X³ − 6X² + 9X + 1, work out d/dX(Y1)|X=4. What does the screen show, and what do you write?
  2. Work out ∫₁³ Y1 dX.
  3. Look at your derivative graph (Y2). For which x is f decreasing?
Show the answers
  1. The screen shows 9.000001; write f′(4) = 9.
  2. 6
  3. Where Y2 is below the x-axis: 1 < x < 3.

Exam efficiency

Worked exam-style example

Question. A particle moves in a straight line with velocity v = 4 sin t − t m s⁻¹, for 0 ≤ t ≤ 4. (a) Find its acceleration when t = 1. (b) Find the value of t > 0 when it is at rest. (c) Find its displacement over the 4 seconds. (d) Find the distance it travels.

  1. Rad mode. Y1 = 4sin(X) − X. (a) d/dX(Y1)|X=1 enter: 1.161208863.

    TI-84 Plus CE lesson 8 screen: Home screen: acceleration, showing the acceleration at t = 1, 1.161208863
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  2. (b) window: Xmin 0, Xmax 4, Ymin −8, Ymax 3, graph. CALC 2:zero around the crossing: X = 2.474576787. On the home screen store it: X,T,θ,n sto→ alpha math (A) enter.

    TI-84 Plus CE lesson 8 screen: Graph of v, showing the velocity graph crossing zero at t = 2.4745768
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  3. (c) ∫₀⁴Y1 dX = −1.385425517. (d) Split at A, where v changes sign: ∫₀^A Y1 dX = 4.080919975 and ∫_A⁴ Y1 dX = −5.466345492, so the distance is 4.080919975 − (−5.466345492) = 9.547265467.

    Displacement can be negative; distance cannot. The part below the axis is counted as positive.

    TI-84 Plus CE lesson 8 screen: Home screen: displacement and distance, showing the displacement −1.385425517 and the distance 9.547265467
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).

What to write down

(a) a = dv/dt = 1.16 m s⁻² at t = 1. (b) v = 0 ⇒ t = 2.47 s. (c) ∫₀⁴ v dt = −1.39 m.

(d) Distance = ∫₀⁴|v| dt = 9.55 m.

Practice

Do these on your own calculator. Write the answers to 3 significant figures unless the task says otherwise.

  1. f(x) = ln(x² + 1). Find f′(2). What does the screen show?
  2. Find ∫₀^π x sin x dx (Rad mode; π is 2nd ^).
  3. Graph y = x·e^(−x) and its derivative graph. Where does the derivative graph cross the x-axis, and what are the coordinates of the maximum of y?
  4. Find the area enclosed by y = x² and y = 2 + x.
  5. y = x³ − 6x² + 9x + 1. Find the x-coordinates where the gradient is −2. (Draw Y2 = d/dX(Y1)|X=X and Y3 = −2, then intersect.)
  6. v = t² − 3t m s⁻¹ for 0 ≤ t ≤ 4. Find the displacement and the distance travelled.
Show the practice answers
  1. The screen shows .8000000107; f′(2) = 0.8.
  2. 3.14 (it is exactly π)
  3. x = 1; maximum (1, 0.368)
  4. They meet at x = −1 and x = 2; area = 4.5
  5. x = 1.42 or x = 2.58
  6. Displacement −2.67 m; distance 6.33 m

Common mistakes

1-minute quick check

Answer these without looking back. Most need no calculation: they check that the key presses have stuck.

  1. Which keys give the d/dx template?
  2. Which keys give the ∫ template?
  3. How do you type Y1 on the home screen quickly?
  4. What do you type in Y2 to draw the derivative of Y1?
  5. Where the derivative graph crosses the x-axis, what does the graph of f have?
Show the quick-check answers
  1. math 8
  2. math 9
  3. alpha trace, then Y1 (or vars → Y-VARS).
  4. d/dX(Y1)|X=X
  5. A turning point (maximum or minimum).

Teaching this lesson (about 55 minutes)

0–5 minStarter: sketch y = x³ − 6x² + 9x + 1 and guess where its gradient is 0.
5–15 minSteps 1–3: d/dx and ∫ templates, and using Y1. Your turn tasks 1 and 2.
15–27 minSteps 4–5: draw the derivative graph, change the window, and link zeros of f′ to the turning points. Your turn task 3.
27–35 minSteps 6–7: CALC ∫f(x)dx and the area between two curves.
35–44 minWorked example: the particle. Displacement against distance.
44–52 minPractice tasks 1–6; check the answers.
52–55 min1-minute quick check.

Students need their own TI-84 Plus CE. With a projector, the calculator-skills guides below have a Show on the board view and an animated walkthrough of the key presses.

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