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TI-84 Plus CE lesson 7: Tables: checking, sign changes and sequences

A table of values is the quickest way to check an answer, compare two models, trap a root between two numbers, or find the first term of a sequence that passes a target. Two screens do all of it: TBLSET to choose the x-values, and TABLE to read them.

Objective

Use TBLSET and TABLE to read values of one or two functions, zoom the step in to locate a root, and answer "smallest n such that …" questions.

By the end, students can:

Which courses this lesson suits

A Level: the sign-change steps are the numerical methods skill of locating a root in an interval.

Before you start

Check mode is on FUNCTION (not SEQ or PARAMETRIC). Clear any old functions in y=.

The key presses, step by step

Every key is shown as it is printed on the calculator, like 2nd or enter. A second function (printed above a key) is 2nd then that key; a menu item is chosen by its number, or by moving to it and pressing enter.

  1. Press y= and type Y1 = X³ − 2X − 7 (X is X,T,θ,n), then enter.

    TI-84 Plus CE lesson 7 screen: Y= editor, showing Y1 = X³ − 2X − 7 in the Y= editor
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  2. Press 2nd window (TBLSET). Set TblStart = 2 and ΔTbl = .1 (type 0.1), with enter after each. Leave Indpnt and Depend on Auto.

    TblStart is the first x in the table; ΔTbl is the gap between x-values.

    TI-84 Plus CE lesson 7 screen: TABLE SETUP, showing TABLE SETUP with TblStart = 2 and ΔTbl = .1
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  3. Press 2nd graph (TABLE). Y1 changes sign between X = 2.2 (−.752) and X = 2.3 (.567), so a root lies between them. Scroll with ▼ and ▲; highlight a value to see it in full at the bottom.

    TI-84 Plus CE lesson 7 screen: TABLE, showing the table of X³ − 2X − 7 from 2 to 2.4 with a sign change between 2.2 and 2.3
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  4. Zoom the step in. Back in TBLSET set TblStart = 2.24 and ΔTbl = .01, then TABLE again. The sign changes between 2.25 (−.1094) and 2.26 (.02318). Check the halfway value 2.255: Y1 is still negative, so the root is between 2.255 and 2.26, and it is 2.26 to 2 d.p.

    Each zoom gives one more decimal place. The halfway check is what shows the rounding is right.

    TI-84 Plus CE lesson 7 screen: TABLE, showing the table from 2.24 to 2.27 with a sign change between 2.25 and 2.26
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  5. Your own x-values. In TBLSET choose Indpnt: Ask. Now TABLE starts empty: type any x, such as 2.255, and enter. Y1 appears next to it: −.043268625.

    Ask is the fastest way to check a set of answers or fill in a table from a question with uneven x-values.

    TI-84 Plus CE lesson 7 screen: TABLE (Indpnt: Ask), showing the table with x = 2.255 typed in and Y1 = −.043268625
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  6. Sequences. For "the smallest n with 500 × 1.08ⁿ > 2000", type Y1 = 500 × 1.08^X, set Indpnt back to Auto, TblStart = 17 and ΔTbl = 1. In TABLE, n = 18 gives 1998 (highlight it: the full value is just under 2000) and n = 19 gives 2157.9. So n = 19.

    X plays the part of n. A step of 1 gives only whole numbers, which is what "smallest n" needs. (mode SEQ is another way, with u(n) in y=; switch back to FUNCTION afterwards.)

    TI-84 Plus CE lesson 7 screen: TABLE, showing the table of 500 × 1.08^X from 17 to 20, passing 2000 between 18 and 19
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).

Your turn: check your understanding

Try these straight after the key presses, on your own calculator, before looking at the answers.

  1. Make a table of y = 2x² − 5 from x = −2 in steps of 0.5. What are y at x = 0.5 and at x = 1.5?
  2. x³ + x − 5 = 0 has one root. Use a table with ΔTbl = 0.1 to find the interval of width 0.1 that contains it.
  3. With Indpnt: Ask, find y = 2x² − 5 at x = 0.37.
Show the answers
  1. −4.5 and −0.5
  2. Between 1.5 and 1.6 (the sign changes there; the root is 1.52 to 3 s.f.).
  3. −4.7262

Exam efficiency

Worked exam-style example

Question. A town's population is modelled by P = 1200 × 0.94^t and a second town's by Q = 300 + 25t, where t is the number of years from now. (a) Find the first whole year in which Q is greater than P. (b) Use a table to find, to 1 decimal place, when the two populations are equal.

  1. (a) Y1 = 1200 × 0.94^X, Y2 = 300 + 25X. TBLSET: TblStart = 0, ΔTbl = 1. TABLE and scroll down: at X = 11, Y1 = 607.56 and Y2 = 575; at X = 12, Y1 = 571.1 and Y2 = 600. So the first whole year is t = 12.

    TI-84 Plus CE lesson 7 screen: TABLE, showing P and Q from t = 10 to 13: Q overtakes P between 11 and 12
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).
  2. (b) TBLSET: TblStart = 11.4, ΔTbl = .1. At X = 11.5, Y1 = 589.05 is still above Y2 = 587.5; at X = 11.6, Y1 = 585.42 is below Y2 = 590. So they are equal between 11.5 and 11.6. The Solver (lesson 6) gives t = 11.52522319, so t = 11.5 to 1 d.p.

    TI-84 Plus CE lesson 7 screen: TABLE, showing P and Q from t = 11.4 to 11.6: they cross between 11.5 and 11.6
    What the screen shows after this step (our drawing of the TI-84 Plus CE screen, not a photo).

What to write down

(a) t = 11: P = 608 > Q = 575; t = 12: P = 571 < Q = 600. So in year 12.

(b) P − Q changes sign between t = 11.5 and t = 11.6; t = 11.5 years (1 d.p.).

Practice

Do these on your own calculator. Write the answers to 3 significant figures unless the task says otherwise.

  1. Show that e^x − 3x = 0 has a root between 1.51 and 1.52, and give the root to 2 decimal places.
  2. Find the smallest whole number n for which 3 × 1.2ⁿ > 100.
  3. With Indpnt: Ask, find g(x) = 5 ÷ (x² + 1) at x = 0.3, 1.7 and 4.2.
  4. The arithmetic series 4 + 7 + 10 + … has Sₙ = n(8 + 3(n − 1)) ÷ 2. Find the smallest n for which Sₙ > 1000.
  5. A student says x = 1.8 is a solution of x³ − 2x − 3 = 0. Use a table to check.
Show the practice answers
  1. f(1.51) = −0.00327 < 0 and f(1.52) = 0.0122 > 0, so there is a root between them; the root is 1.51 (2 d.p.).
  2. n = 20 (n = 19 gives 95.8; n = 20 gives 115)
  3. 4.59, 1.29 and 0.268
  4. n = 26: S₂₅ = 1000, which is not more than 1000, and S₂₆ = 1079.
  5. f(1.8) = −0.768, not 0, so x = 1.8 is not a solution.

Common mistakes

1-minute quick check

Answer these without looking back. Most need no calculation: they check that the key presses have stuck.

  1. Which keys open TBLSET?
  2. Which keys open the TABLE?
  3. What does ΔTbl set?
  4. How do you type your own x-values?
  5. What do you need to see in the table to say there is a root?
Show the quick-check answers
  1. 2nd window
  2. 2nd graph
  3. The step between x-values.
  4. TBLSET → Indpnt: Ask.
  5. A change of sign in Y between two x-values (for a continuous function).

Teaching this lesson (about 55 minutes)

0–5 minStarter: without a calculator, is x³ − 2x − 7 positive or negative at x = 2 and at x = 3? What does that tell you?
5–15 minSteps 1–3: Y1, TBLSET, TABLE and the first sign change.
15–22 minStep 4: zooming ΔTbl in and the halfway check. Your turn task 2.
22–30 minSteps 5–6: Indpnt Ask and sequences. Your turn tasks 1 and 3.
30–40 minWorked example: the two towns.
40–52 minPractice tasks 1–5; check the answers.
52–55 min1-minute quick check.

Students need their own TI-84 Plus CE. With a projector, the calculator-skills guides below have a Show on the board view and an animated walkthrough of the key presses.

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