Valentine’s Day maths for IB Maths SL and HL
A ready-to-teach lesson for 14 February: a 5-minute starter, a 35-minute main activity on a heart made from simple shapes, the probability that nobody draws their own name in a secret card swap and the area of a heart-shaped curve, an extension and full worked answers.
- Level
- IB Maths SL and HL (AA and AI)
- Time
- 40 minutes, plus a 10-minute extension
- Topics
- Area and perimeter of composite shapes; Counting and probability; Graphs of implicitly defined curves; Definite integrals and area; Optimisation with a GDC
- Equipment
- The starter is non-calculator. A GDC is needed for the main activity.
Suggested timings
| Part | Time | What |
|---|---|---|
| Starter | 5 min | Quick questions on the board |
| Main: task A | 10 min | A heart from simple shapes |
| Main: task B | 13 min | Secret card swap |
| Main: task C | 12 min | A heart-shaped curve |
| Extension | 10 min | Fast finishers or homework |
Starter (5 minutes)
No GDC.
- Find the area of a circle of radius 3, in terms of π.
- Work out 4!.
- Two fair coins are tossed. Find the probability of two heads.
- Solve |x|2/3 = 4.
Main activity (35 minutes)
Task A: A heart from simple shapes (10 min)
A heart is made from a square of side s cm, turned to stand on a corner, with a semicircle on each of its two upper sides.
- Take s = 10. Find the area of the heart, exactly and to 3 significant figures.
- Find the perimeter of the heart, to 3 significant figures.
- A card designer wants a heart of this shape with area 500 cm2. Find s, to 3 significant figures.
Task B: Secret card swap (13 min)
Four friends each write their name on a card. The cards are shuffled and each friend takes one at random.
- In how many different ways can the four cards be handed out?
- List the ways in which nobody gets their own card. Find the probability that nobody gets their own card.
- Find the probability that exactly one friend gets their own card.
- (HL) For a class of 30, the probability that nobody gets their own card is very close to 1/e. Find 1/e to 3 significant figures.
Task C: A heart-shaped curve (12 min)
The curve x2 + (y − |x|2/3)2 = 1 is heart-shaped. Plot it on your GDC as two functions.
- Show that the curve is y = |x|2/3 ± √(1 − x2) for −1 ≤ x ≤ 1. Find where it crosses the y-axis.
- Show that the vertical distance between the two halves of the curve at x is 2√(1 − x2). Hence explain why the area inside the heart equals the area of a circle of radius 1, and write it down.
- Use your GDC to find the highest points of the heart, to 3 significant figures.
Extension (10 minutes)
A matching problem.
- People each choose a whole number from 1 to 20 at random. Find the probability that two people choose the same number. How many people are needed for the probability that at least two of them match to be more than ½?
For teachers
Teacher notes and full worked answers
- Run task B for real: shuffle four name cards with four volunteers a few times before working it out.
- In task B (c), many students think ‘exactly three right’ is possible: ask why it is not.
- Task C is a good GDC-skills task: students need both halves of the curve and must use |x| correctly.
Starter
- 9π
- π × 32 = 9π
- 24
- 4 × 3 × 2 × 1 = 24
- 1/4
- ½ × ½ = ¼
- x = 8 or −8
- |x| = 43/2 = 8, so x = ±8.
Task A: A heart from simple shapes
- 100 + 25π ≈ 179 cm2
- Square: 102 = 100. Two semicircles of radius 5 make one circle: π × 52 = 25π.
- 100 + 25π = 178.5…, which is 179 cm2 (3 s.f.).
- 51.4 cm
- Two straight sides: 20 cm. Two semicircular arcs make one circle of diameter 10: 10π.
- 20 + 10π = 51.41…
- 16.7 cm
- Area = s2 + π(s/2)2 = s2(1 + π/4).
- s2 = 500 ÷ 1.7853… = 280.0…, so s = 16.73…
Task B: Secret card swap
- 24
- 4! = 24
- 9 ways; 3/8
- Call the friends A, B, C, D. The orders with nobody in their own place are BADC, BCDA, BDAC, CADB, CDAB, CDBA, DABC, DCAB, DCBA: 9 of them.
- 9/24 = 3/8
- 1/3
- Choose the lucky friend: 4 ways. The other three must all miss: 2 ways (for example BCA or CAB).
- 4 × 2 = 8, and 8/24 = 1/3.
- 0.368
- 1/e = 0.36787…
- The exact probability for 30 people agrees with 1/e to many decimal places.
Task C: A heart-shaped curve
- (0, 1) and (0, −1)
- (y − |x|2/3)2 = 1 − x2, so y − |x|2/3 = ±√(1 − x2).
- At x = 0: y = ±1.
- π
- Top minus bottom: (|x|2/3 + √(1 − x2)) − (|x|2/3 − √(1 − x2)) = 2√(1 − x2).
- That is the same as for the circle x2 + y2 = 1, so the area is the same: ∫−11 2√(1 − x2) dx = π.
- (±0.617, 1.51)
- Maximise y = x2/3 + √(1 − x2) for 0 < x < 1: the maximum is at x = 0.6166…, y = 1.5117…
- By symmetry the other top is at x = −0.617.
Extension
- 1/20; 6 people
- Two people: the second matches the first with probability 1/20.
- With k people, P(no match) = (20 × 19 × … × (21 − k)) ÷ 20k.
- k = 5: P(no match) = 0.581…, so P(match) = 0.419. k = 6: P(no match) = 0.436…, so P(match) = 0.564 > ½.
The same answers are in the answers PDF. Every answer was recomputed by computer before publishing.
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