Maths about me: a first-lesson icebreaker for IB Maths
A first lesson of the year that gets everyone talking and doing maths: number facts built from a birthday, ‘Who am I?’ riddles that preview sequences, logs and counting, and the four 4s challenge. Everything is on paper and nothing personal is collected.
- Level
- IB Maths SL and HL (AA and AI)
- Time
- 40 minutes, plus a 10-minute extension
- Topics
- Prime factorisation and number; Sequences and series; Exponents and logarithms; Counting
- Equipment
- The starter is non-calculator. A GDC is useful for task A.
Suggested timings
| Part | Time | What |
|---|---|---|
| Starter | 5 min | Quick questions on the board |
| Main: task A | 12 min | Maths about me |
| Main: task B | 10 min | ‘Who am I?’ in pairs |
| Main: task C | 13 min | Four 4s |
| Extension | 10 min | Fast finishers or homework |
Starter (5 minutes)
‘Who am I?’ riddles on the board as students arrive.
- I am a positive integer. My square is 4 more than 3 times me. Who am I?
- I am the 10th term of the arithmetic sequence 7, 11, 15, … Who am I?
- I am log2 64 + log3 81. Who am I?
- I am the number of ways to arrange the letters of the word MATHS in a row. Who am I?
Main activity (35 minutes)
Task A: Maths about me (12 min)
Work through Alex’s made-up numbers first. Then write the same facts about your own numbers on paper.
- Alex was born on day 28 of month 6 in 2009. Write 28 and 2009 as products of prime factors.
- Find the HCF and the LCM of 28 and 2009.
- The arithmetic sequence 6, 28, 50, … starts with Alex’s month and day. Which term is closest to 2009, and what is it?
- Solve 2x = 28, giving x to 3 significant figures.
Task B: ‘Who am I?’ in pairs (10 min)
Solve these with a partner. Then each write a riddle of your own, on a topic from last year, with exactly one answer and swap.
- I am a three-digit multiple of 9 and of 11, and my hundreds digit is 7. Who am I?
- I am the sum of the first n odd numbers, and I am between 200 and 250. Who am I, and what is n?
- I am the sum to infinity of a geometric series with first term 12 and second term 4. Who am I?
- I am the positive integer n with nC2 = 45. Who am I?
Task C: Four 4s (13 min)
Use exactly four 4s to make each target. Allowed: +, −, ×, ÷, brackets, powers, √ and ! (4! = 24). You may join two 4s to make 44. Other answers are possible.
- Make 24 using only +, −, × and ÷.
- Make 64.
- Make 19.
- Make 1024.
Extension (10 minutes)
For fast finishers.
- Prove that the sum of any two-digit number and the number with its digits reversed is a multiple of 11.
- Find every two-digit number that is 4 times the sum of its digits.
For teachers
Teacher notes and full worked answers
- Nothing personal is collected: students work on paper, and nothing is typed into the site or stored. If a student would rather not use a real birthday, any date works.
- Pairs for task B: each student writes one riddle with exactly one answer and swaps with a partner, who checks that only one number fits.
- Mindset prompts for the first lesson (for you to read out or put on the board; nothing is collected or stored): ‘A time maths felt hard, and what helped’; ‘One topic from last year I could teach a friend’; ‘What I do when I am stuck’; ‘How I want this class to feel’.
- The riddles preview the first topics of the course: sequences and series, exponents and logarithms, and counting.
Starter
- 4
- x2 = 3x + 4, so (x − 4)(x + 1) = 0
- x = 4 (the other root, −1, is not positive)
- 43
- u10 = 7 + 9 × 4 = 43
- 10
- log2 64 = 6 and log3 81 = 4
- 6 + 4 = 10
- 120
- 5! = 5 × 4 × 3 × 2 × 1 = 120
Task A: Maths about me
- 28 = 22 × 7 and 2009 = 72 × 41
- 28 = 4 × 7 = 22 × 7
- 2009 = 7 × 287 = 7 × 7 × 41, and 41 is prime
- HCF = 7, LCM = 8036
- HCF = 7 (the only common prime, to the lower power)
- LCM = 22 × 72 × 41 = 8036
- The 92nd term, 2008
- un = 6 + 22(n − 1)
- 6 + 22(n − 1) = 2009 gives n − 1 = 91.04…
- u92 = 6 + 22 × 91 = 2008 (and u93 = 2030)
- x = 4.81
- x = log2 28 = ln 28 / ln 2 = 4.807…
Task B: ‘Who am I?’ in pairs
- 792
- Three-digit multiples of 99: 198, 297, …, 990.
- Only 792 starts with 7.
- 225, with n = 15
- 1 + 3 + … + (2n − 1) = n2
- The only square between 200 and 250 is 225 = 152.
- 18
- r = 4/12 = 1/3
- S∞ = 12 / (1 − 1/3) = 18
- 10
- n(n − 1)/2 = 45, so n2 − n − 90 = 0
- (n − 10)(n + 9) = 0, so n = 10
Task C: Four 4s
- 4 × 4 + 4 + 4 = 24
- 16 + 8 = 24
- (4 + 4) × (4 + 4) = 64
- 8 × 8 = 64
- 4! − 4 − 4/4 = 19
- 24 − 4 − 1 = 19
- 44 + 4/4 = 1024
- 4 + 4/4 = 5 and 45 = 1024
Extension
- (10a + b) + (10b + a) = 11(a + b)
- Write the number as 10a + b; its reverse is 10b + a.
- The sum is 11a + 11b = 11(a + b), a multiple of 11.
- 12, 24, 36 and 48
- 10a + b = 4(a + b) gives b = 2a.
- a = 1, 2, 3, 4 give 12, 24, 36, 48.
The same answers are in the answers PDF. Every answer was recomputed by computer before publishing.
Practise the topics
- Sequences and series (AA SL)
- Exponentials and logarithms (AA SL)
- Counting and the binomial theorem (AA HL)
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