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IB Maths AI SL · Unit 1: Number and Algebra

IB Maths AI SL Sequences and Series Questions

Exam-style IB Maths AI SL sequences and series questions with worked solutions. Start with the 5 fully worked examples below — each is solved step by step the way an IB examiner expects — then try the practice questions and check your working against the mark scheme.

Practise Sequences and Series questions → AI SL formula booklet

What you need to know

Common difference, nth term, and sum formulas. In SL AI these are almost always dressed up as a real-world context: seat rows in a stadium, monthly salary rises, or step-by-step savings. Arithmetic sequences and series overview →

Geometric progressions underpin every SL AI compound interest, depreciation, and finance question. Mastering the r < 1 vs r > 1 case unlocks half of Paper 2's financial modelling questions. Geometric sequences and compound interest overview →

What's examined in AI SL sequences and series

The question bank covers these sequences and series question types (number of questions in brackets):

Key formulas

The n-th term of an arithmetic sequence
\(u_n = u_1 + (n-1)d\)
Sum of n terms of an arithmetic sequence
\(S_n = \tfrac{n}{2}\bigl(2u_1 + (n-1)d\bigr) = \tfrac{n}{2}(u_1 + u_n)\)
The n-th term of a geometric sequence
\(u_n = u_1 \cdot r^{\,n-1}\)
Sum of n terms of a geometric sequence
\(S_n = \frac{u_1(r^n - 1)}{r - 1} = \frac{u_1(1 - r^n)}{1 - r},\ r \ne 1\)

In the same notation as the IB formula booklet. All AI SL formulas →

Sequences and Series worked examples

Worked example 1: nth term of an arithmetic sequence · easy

An arithmetic sequence has a first term of $u_1 = 12$ and a common difference of $d = 4$. Find $u_{25}$.

Solution

1. Recall $u_n = u_1 + (n - 1)d$.

2. Substitute $u_1 = 12$, $d = 4$, $n = 25$.

3. Set up: $u_{25} = 12 + (25 - 1)(4)$.

4. Simplify the bracket: $u_{25} = 12 + (24)(4)$.

5. Evaluate: $u_{25} = 12 + 96 = \mathbf{108}$.

Examiner tip: Watch the $(n-1)$: for the 25th term you add $d$ exactly $24$ times, not $25$ times.

Worked example 2: Total distance travelled by a bouncing ball · medium

A ball is dropped from $10\text{ m}$. After each bounce it rebounds to $80\%$ of its previous height. Calculate the total vertical distance travelled from the moment it is dropped until it hits the ground for the 6th time.

Solution

1. Recognise the initial drop is $10\text{ m}$ (down only). The 5 subsequent rebounds are up-and-down each.

2. Identify the rebound sequence: $u_1 = 10 \times 0.8 = 8\text{ m}$, $r = 0.8$.

3. Use $S_n = \frac{u_1(1 - r^n)}{1 - r}$ with $n = 5$.

4. Evaluate: $S_5 = \frac{8(1 - 0.8^5)}{0.2} = \frac{8(0.67232)}{0.2} = 26.8928\text{ m}$.

5. Total: initial drop $+\ 2 \times$ (sum of rebounds) $= 10 + 2(26.8928)$.

6. State: total distance $= 63.7856 \implies \mathbf{63.8\text{ m}}$.

Examiner tip: Between bounces the ball travels the rebound distance TWICE (up and down), so double the rebound sum. The initial drop is only once, so don't double that.

Worked example 3: Sum to infinity of a geometric series · easy

An infinite geometric series has $u_1 = 18$ and common ratio $r = 0.6$. Find the exact sum to infinity.

Solution

1. Recall $S_\infty = \frac{u_1}{1 - r}$.

2. Check convergence: $|0.6| < 1$, so $S_\infty$ exists.

3. Substitute: $S_\infty = \frac{18}{1 - 0.6}$.

4. Simplify: $S_\infty = \frac{18}{0.4}$.

5. Evaluate: $\mathbf{S_\infty = 45}$.

Examiner tip: The sum to infinity only exists when $-1 < r < 1$. If $|r| \ge 1$ the series diverges and no finite sum exists.

Worked example 4: Solving for n in an arithmetic series · medium

An arithmetic sequence has $u_1 = 5$ and $d = 2$. Find the minimum number of terms required for the sum of the series to strictly exceed $150$.

Solution

1. Recall: $S_n = \frac{n}{2}(2u_1 + (n - 1)d)$.

2. Set up: $\frac{n}{2}(2(5) + (n - 1)2) > 150$.

3. Simplify: $\frac{n}{2}(2n + 8) > 150$.

4. Expand: $n^2 + 4n > 150 \implies n^2 + 4n - 150 > 0$.

5. Solve $n^2 + 4n - 150 = 0$ on the GDC: positive root $n \approx 10.42$.

6. Conclude: smallest integer $n = \mathbf{11}$.

Examiner tip: Instead of manipulating the quadratic algebraically you can graph $Y_1 = 0.5x(10 + 2(x-1))$ and $Y_2 = 150$ on the GDC and use the intersection tool directly.

Worked example 5: Arithmetic vs geometric growth crossover · hard

Sequence A is arithmetic with $u_n = 50 + 10n$. Sequence B is geometric with $v_n = 20(1.5)^n$. Find the smallest integer $n$ for which $v_n$ is strictly greater than $u_n$.

Solution

1. Set up the inequality: $20(1.5)^n > 50 + 10n$.

2. Recognise that mixing exponential and linear forces a graphical/numerical solve.

3. Enter $Y_1 = 20(1.5)^x$ and $Y_2 = 50 + 10x$ on the GDC.

4. Use the intersection tool (G-Solv $\to$ ISCT).

5. Read: intersection at $x = 4.098\ldots$

6. Conclude: smallest integer $n = \mathbf{5}$.

Examiner tip: An exponential model will always eventually outgrow any linear model. Use the GDC table or intersection feature to find the crossover point.

Try these IB Maths AI SL sequences and series questions

Three questions from the bank, easiest first. Mark schemes and AI marking of your written working are in the practice area.

Question 1 · easy · 4 marks · Paper 1

An arithmetic sequence has the following first three terms: \(4, 9, 14, \dots\)

  1. Find the common difference, \(d\).

  2. Find the value of the 15th term, \(u_{15}\).

  3. Find the sum of the first 15 terms of the sequence, \(S_{15}\).

Attempt it and see the mark scheme →

Question 2 · medium · 3 marks · Paper 1

Using the summation tool on your Graphic Display Calculator, evaluate the following arithmetic series: \[\sum_{k=1}^{12} (5k - 2)\] Show the values you entered into your calculator.

Attempt it and see the mark scheme →

Question 3 · hard · 4 marks · Paper 1

How many terms of the arithmetic series \(11 + 16 + 21 + 26 + \dots\) are needed to strictly exceed a sum of \(450\)? Use your GDC to solve.

Attempt it and see the mark scheme →

All 37 sequences and series questions with mark schemes →

FAQ

How many IB Maths AI SL sequences and series questions are there?

There are 37 exam-style sequences and series questions in the AI SL question bank (Paper 1: 24 · Paper 2: 13), graded 6 easy, 12 medium, 7 hard, 8 very hard, 4 starter. Every question has a full IB-style mark scheme (M, A and R marks).

Is sequences and series on Paper 1 or Paper 2?

Both. In the bank, Paper 1: 24 · Paper 2: 13. Practise with your GDC — AI papers expect calculator methods throughout.

Where can I get the mark schemes?

Open the AI SL Unit 1 practice page: every question has a step-by-step IB-style mark scheme, and you can photograph your working for instant AI marking. The worked examples on this page are free.

More AI SL Unit 1 topics

Sequences and Series in other IB Maths courses

← All IB Maths AI SL topics