IA idea · Pure maths, number & proof
The Collatz conjecture: what can we say about stopping times?
Research question
How are the stopping times of the Collatz sequence distributed for starting values up to 10⁶, and does a simple probabilistic model explain why sequences tend to fall?
Adapt it: change the place, the data or the comparison until the question is yours.
Why it makes a good exploration
The Collatz conjecture is unsolved, so you cannot prove it — but you can investigate it. A heuristic argument that on average each step multiplies by about 3/4 explains why sequences usually come down, and is a lovely use of expected value and logarithms.
The mathematics you'll need
- Iteration and sequences
- Statistics of stopping times
- Expected value and geometric means
- Logarithms to model average decrease
- Honest discussion of heuristic vs proof
Course labels show where a technique sits; using maths from outside your course is fine if you explain it clearly and say it is new to you.
Where the data comes from
Generate data with a spreadsheet or short program; compare with OEIS records.
- OEIS (On-Line Encyclopedia of Integer Sequences) — Check a sequence you have found and read its known formulas and references.
Cite every source in a footnote where you use it and in your bibliography. Check the licence of any dataset you download.
A possible outline
- Explain the rule and the conjecture.
- Generate stopping times and analyse their distribution.
- Build the probabilistic model.
- Test the model's prediction of average stopping time against log n.
- Reflect on why heuristics are not proofs.
Pitfalls that cost marks
- Claiming to prove the conjecture.
- Huge tables with no analysis.
- Not explaining the program used.
Showing personal engagement
- Find a starting number with a long sequence yourself.
- Explore a variant (5n + 1) and see it fail.
- Discuss why famous mathematicians consider it hard.
See Criterion C: personal engagement for what examiners look for.
Taking it further
Fit stopping time against ln n and compare the gradient with your model's prediction.
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